Don't use "operator ="
Some compilers don't like operator = defined on members of union members
either. Reported by Ginn Chen for Sun Studio compilers.
diff --git a/src/hb-open-type-private.hh b/src/hb-open-type-private.hh
index cde6414..a0ecc2e 100644
--- a/src/hb-open-type-private.hh
+++ b/src/hb-open-type-private.hh
@@ -370,7 +370,7 @@
class BEInt<Type, 2>
{
public:
- inline class BEInt<Type,2>& operator = (Type i) { hb_be_uint16_put (v,i); return *this; }
+ inline void set (Type i) { hb_be_uint16_put (v,i); }
inline operator Type () const { return hb_be_uint16_get (v); }
inline bool operator == (const BEInt<Type, 2>& o) const { return hb_be_uint16_cmp (v, o.v); }
inline bool operator != (const BEInt<Type, 2>& o) const { return !(*this == o); }
@@ -380,7 +380,7 @@
class BEInt<Type, 4>
{
public:
- inline class BEInt<Type,4>& operator = (Type i) { hb_be_uint32_put (v,i); return *this; }
+ inline void set (Type i) { hb_be_uint32_put (v,i); }
inline operator Type () const { return hb_be_uint32_get (v); }
inline bool operator == (const BEInt<Type, 4>& o) const { return hb_be_uint32_cmp (v, o.v); }
inline bool operator != (const BEInt<Type, 4>& o) const { return !(*this == o); }
@@ -391,7 +391,7 @@
template <typename Type>
struct IntType
{
- inline void set (Type i) { v = i; }
+ inline void set (Type i) { v.set (i); }
inline operator Type(void) const { return v; }
inline bool operator == (const IntType<Type> &o) const { return v == o.v; }
inline bool operator != (const IntType<Type> &o) const { return v != o.v; }
