blob: 916f5c9aa22f17ffc7fd405912494d3cb5823828 [file] [log] [blame]
// Copyright 2017 The Chromium Authors. All rights reserved.
// Use of this source code is governed by a BSD-style license that can be
// found in the LICENSE file.
import FlutterMacOS
import Foundation
public class UrlLauncherPlugin: NSObject, FlutterPlugin {
public static func register(with registrar: FlutterPluginRegistrar) {
let channel = FlutterMethodChannel(
name: "plugins.flutter.io/url_launcher",
binaryMessenger: registrar.messenger)
let instance = UrlLauncherPlugin()
registrar.addMethodCallDelegate(instance, channel: channel)
}
public func handle(_ call: FlutterMethodCall, result: @escaping FlutterResult) {
let urlString: String? = (call.arguments as? [String: Any])?["url"] as? String
switch call.method {
case "canLaunch":
guard let unwrappedURLString = urlString,
let url = URL.init(string: unwrappedURLString)
else {
result(invalidURLError(urlString))
return
}
result(NSWorkspace.shared.urlForApplication(toOpen: url) != nil)
case "launch":
guard let unwrappedURLString = urlString,
let url = URL.init(string: unwrappedURLString)
else {
result(invalidURLError(urlString))
return
}
result(NSWorkspace.shared.open(url))
default:
result(FlutterMethodNotImplemented)
}
}
}
/// Returns an error for the case where a URL string can't be parsed as a URL.
private func invalidURLError(_ url: String?) -> FlutterError {
return FlutterError(
code: "argument_error",
message: "Unable to parse URL",
details: "Provided URL: \(String(describing: url))")
}