blob: 00a404c4777faabf20588bca1da724c095c9b748 [file] [edit]
// Copyright (C) 2024 The Android Open Source Project
//
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
import {BigintMath} from './bigint_math';
import {HighPrecisionTimeSpan} from './high_precision_time_span';
import {errResult, okResult, Result} from './result';
import {duration} from './time';
/**
* Work out an appropriate "resolution" for a given time span stretched over a
* given number of pixels, rounded down to the nearest power of 2.
*
* @param timeSpan The span of time to represent.
* @param widthPx How many pixels we have to represent the time span.
* @returns The resultant resolution, or an error if the input parameters are
* invalid.
*/
export function calculateResolution(
timeSpan: HighPrecisionTimeSpan,
widthPx: number,
): Result<duration> {
if (widthPx <= 0) {
return errResult('Parameter "widthPx" must be greater than 0.');
}
const dur = timeSpan.duration;
if (dur <= 0) {
return errResult(
'The duration of the "timeSpan" parameter must be greater than 0.',
);
}
// Work out how much time corresponds to one pixel.
const timePerPixel = Number(dur) / widthPx;
// Convert to a bigint and round down to the nearest power of 2.
return okResult(BigintMath.bitFloor(BigInt(Math.floor(timePerPixel))));
}